$$ \newcommand{\cis}{\operatorname{cis}} \newcommand{\norm}[1]{\left\|#1\right\|} \newcommand{\paren}[1]{\left(#1\right)} \newcommand{\sq}[1]{\left[#1\right]} \newcommand{\abs}[1]{\left\lvert#1\right\rvert} \newcommand{\set}[1]{\left\{#1\right\}} \newcommand{\ang}[1]{\left\langle#1\right\rangle} \newcommand{\floor}[1]{\left\lfloor#1\right\rfloor} \newcommand{\ceil}[1]{\left\lceil#1\right\rceil} \newcommand{\C}{\mathbb{C}} \newcommand{\D}{\mathbb{D}} \newcommand{\R}{\mathbb{R}} \newcommand{\Q}{\mathbb{Q}} \newcommand{\Z}{\mathbb{Z}} \newcommand{\N}{\mathbb{N}} \newcommand{\F}{\mathbb{F}} \newcommand{\T}{\mathbb{T}} \renewcommand{\S}{\mathbb{S}} \newcommand{\intr}{{\large\circ}} \newcommand{\limni}[1][n]{\lim_{#1\to\infty}} \renewcommand{\Re}{\operatorname{Re}} \renewcommand{\Im}{\operatorname{Im}} $$
Due: February 4th, 2021

Math 104 Assignment 2

  1. Translation of suprema

    Suppose that $(F, \preceq)$ is an ordered field, that $H \subseteq F$, and that $a \in F$. Suppose further that $\sup H = t \in F$. Finally, let $H+a = \set{x + a \mid x \in H} \subseteq F$. Prove that $H+a$ has a supremum in $F$, and that $\sup(H+a) = \sup(H)+a$.

  2. Some useful facts

    Prove the following useful facts.

    1. If $T \subseteq \Z$ is non-empty and bounded above in $\R$, then $\sup T \in T$. (In particular, $\sup T \in \Z$.)
    2. Suppose that $\emptyset \subsetneq E_1 \subseteq E_2 \subseteq \R$. If $E_2$ is bounded above, then $\sup E_1$ exists (in $\R$) and $\sup E_1 \leq \sup E_2$.

      (Note: the symbol "$\subsetneq$" means "is a proper subset of", so $A \subsetneq B$ means $A \subseteq B$ and $A \neq B$. Thus $\emptyset \subsetneq E_1$ means "$E_1$ is non-empty". In contrast, the symbol $\nsubseteq$ means "is not a subset of". The symbol "$\subset$" is inconsistently used, usually meaning $\subsetneq$ but sometimes meaning $\subseteq$, depending on the author.)

    3. If $x, y \in \R$ with $0 \leq x \leq y$ then $x^2 \leq y^2$. Moreover, assuming that $x^{1/2}, y^{1/2}$ exist in $\R$ with $0 \leq x^{1/2}, y^{1/2}$, prove that $x^{1/2}\leq y^{1/2}$.

    4. If $S$ is an ordered set, $E, F \subseteq S$ have suprema in $S$, and they have the property that for every $e \in E$ there is $f \in F$ with $e \preceq f$, then $\sup E \preceq \sup F$.
  3. Some facts about suprema

    1. Let $(S, \preceq)$ be an ordered set, and $t \in S$. Prove that $\sup\set{s \in S \mid s \preceq t} = t$.
    2. Show by example that Part A need not hold if the $\preceq$ in the definition of the set is replaced by $\prec$.
    3. Show that, nonetheless, if $x \in \R$ then $$\sup\set{q \in \Q \mid q \lt x} = x.$$ (Note that, as a result, every real number is the supremum of some set of rational numbers.)
  4. Suprema in the rationals are suprema in the reals

    1. Suppose that $E \subset \Q$ has least upper bound $t \in \Q$. Show that $t$ is also the least upper bound of $E \subset \R$.
    2. Prove that $\set{q \in \Q \mid q^2 \lt 2}$ does not have a least upper bound in $\Q$ (and so $\Q$ indeed does not have the Least Upper Bound Property).
  5. Properties of irrational numbers

    1. Prove that if $q \in \Q$ and $t \in \R\setminus \Q$, then $q + t \in \R\setminus\Q$.
    2. Prove that if $q \in \Q$ and $t \in \R\setminus \Q$, then $qt \in \set{0}\cup(\R\setminus\Q)$.
    3. Prove that if $x, y \in \R$ with $x \lt y$, there is some $t \in \R\setminus\Q$ with $x \lt t \lt y$.

Here are some further problems to think about out of interest. You do not need to attempt them, nor should you submit them with the assignment. They are coloured by approximate difficulty: easy/medium/hard.